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Official M16: Refinement

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  • fdsakhfduewhfiuffdsakhfduewhfiuf Member Posts: 604 Arc User
    Enchantment values still scale between different level 70 zones.

    Radiant in Protector's Enclave gives 1080 power.
    Radiant in Dread Ring gives 420 power.

    Is this a bug or intended behavior?
  • fuzzmeisterjfuzzmeisterj Member Posts: 55 Arc User
    onodrain said:


    The good part of the insignia change is that you can get legendary insignias. The poorly thought out part is...how many insignia types there are. Non-hoarders are at a huge disadvantage in upgrading. As we need to have 8 of the common, 4 rare and 1 epic version of each insignia we want to upgrade. The current insignia is not considered part of it. So in total, 2 epic, 4 rare and 8 common. How many different types of insignias are there? Now I have no inventory. Please come up with another way to upgrade insignias. Having that many types of insignias in inventory is insane.


    The Crescent Insignia of Initiative at epic level has the orange coloration of the legendary level. When I click to upgrade, it shows the legendary insignia as purple, rather than orange.

    For one thing, stats double from epic to legendary, so making it too easy might unbalance things. There are 6 normal types I think and 3 from the zen store
  • kopisusu36b#1324 kopisusu36b Member Posts: 19 Arc User
    edited March 2019
    Why insignia refinement must use same type and with different rank insignia as reagent? why not using mark of potency or enchanting stone?
    Will you give us extra bag slot? Insignias will occupied more slot in inventory imho.
    Post edited by kopisusu36b#1324 on
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User

    Why insignia refinement must using insignia same type and with different rank as reagent? why not using mark of potency or enchanting stone?
    Will you give us extra bag slot? Insignias will occupied more slot in inventory imho.

    The goal, one imagines, is to make those previously useless green and blue insignias that you get from skill nodes and the like useful again.
  • onodrainonodrain Member Posts: 334 Arc User

    Why insignia refinement must using insignia same type and with different rank as reagent? why not using mark of potency or enchanting stone?
    Will you give us extra bag slot? Insignias will occupied more slot in inventory imho.

    The goal, one imagines, is to make those previously useless green and blue insignias that you get from skill nodes and the like useful again.
    You missed his point. The point is the same one I made...there are too many insignias. They take up too much room in inventory. That is the point.

    I do not have the inventory space needed to be a hoarder, nor do I want to become one. People who are hoarders will benefit from this much more than people who are not.
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User
    vendood said:

    My own guess would be that they meant to have Insignias have some sort of use/value - we've seen threads with the 'what do I do with these junk green insignia?' type topics. But the storage space is an issue and a problem, as is the RNG on getting the right matches for your current insignia.

    It would be better to have insignia work somewhat like artifact feeding used to: Epic insignia needs points, you feed lesser insignia into it to gain points. Matching insignia gives double points. Feed in anything until it pops. Boom, all insignia are now useful, no hoarding needed, inventory space conserved.

    I wouldn't mind a system where you can break insignias down into "Insignia essence" of the respective class (green, blue, purple,), and then creating an insignia of the proper type requires 2-4 essences of the proper rank.

    Have it also require residuum for the lulz.
  • nisckisnisckis Member, NW M9 Playtest Posts: 655 Arc User

    I wouldn't mind a system where you can break insignias down into "Insignia essence" of the respective class (green, blue, purple,), and then creating an insignia of the proper type requires 2-4 essences of the proper rank.

    Have it also require residuum for the lulz.

    I like this proposal :+1: , just in case the proposal of mark of potency and/or enchanting stone is not good enough.
  • nisckisnisckis Member, NW M9 Playtest Posts: 655 Arc User
    edited March 2019
    Added the average number of wards needed for upgrading an item at 1% chance, thanks @muminekm#3459 for noticing I was outputting the probability of failure of every roll with the new system, not how many wards in average are needed with the new system


    I decided to run some simulations because those numbers people were giving about ward vs coal chance looked quite misleading.

    These are the result calculated, far away from the numbers people were using asking for a coal price reduction.
    Rolls=1.000.000
    Break streak activated=2.811
    Natural success=9.853
    Success=12.664
    Failure=987.336
    Failure chance=0,987336
    Wards needed per enchant=77,96

    Rolls=1.000.000
    Break streak activated=2.826
    Natural success=9.912
    Success=12.738
    Failure=987.262
    Failure chance=0,987262
    Wards needed per enchant=77,50

    Rolls=1.000.000
    Break streak activated=2.855
    Natural success=9.863
    Success=12.718
    Failure=987.282
    Failure chance=0,987282
    Wards needed per enchant=77,62

    this is the class used, yes, it's Java.
    link for online execution (http://tpcg.io/dd3bfD)
    package neverwinter; import java.security.SecureRandom; public class Neverwinter { private static final int NUM_ROLLS = 1000000; public static void main(String[] args) { int[] rolls = new SecureRandom().ints(NUM_ROLLS, 1, 101).toArray(); int breakStreak = 0; final int MAX_BREAK_STREAK = 150; int success = 0; int breakStreakActivated = 0; for (int roll : rolls) { if (breakStreak >= MAX_BREAK_STREAK) { success++; breakStreak = 0; breakStreakActivated++; continue; } if (roll == 1) { success++; breakStreak = 0; continue; } breakStreak++; } System.out.printf("Rolls=%,d", NUM_ROLLS); System.out.println(); System.out.printf("Break streak activated=%,d", breakStreakActivated); System.out.println(); System.out.printf("Natural success=%,d", success - breakStreakActivated); System.out.println(); System.out.printf("Success=%,d", success); System.out.println(); System.out.printf("Failure=%,d", NUM_ROLLS - success); System.out.println(); System.out.printf("Failure chance=%,f", ((double) NUM_ROLLS - success) / NUM_ROLLS); System.out.println(); System.out.printf("Wards needed per enchant=%,f", ((double) (NUM_ROLLS - success)) / success); } }


    So it's giving a number of wards around 77 so:
    - If you do you have access to enough wards it is wiser using them.
    - If you do not have access to enough cheap wards, probably you should go for Coal that you can get cheaper more easily.
    - If you are an unlucky hero then it will be wiser going for Coal too.

    With this number, should Coal be reduced in price? Well, I would not do it, that way you should chose between playing safe (and easier to get a cheap Coal) or playing risky (and harder getting enough cheap wards).
    Post edited by nisckis on
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User
    nisckis said:

    I decided to run some simulations because those numbers people were giving about ward vs coal chance looked quite misleading.

    These are the result calculated, far away from the numbers people were using asking for a coal price reduction.

    Rolls=1.000.000
    Break streak activated=2.845
    Natural success=9.956
    Success=12.801
    Failure=987.199
    Failure chance=0,987199

    Rolls=1.000.000
    Break streak activated=2.812
    Natural success=10.068
    Success=12.880
    Failure=987.120
    Failure chance=0,987120

    Rolls=1.000.000
    Break streak activated=2.857
    Natural success=9.946
    Success=12.803
    Failure=987.197
    Failure chance=0,987197

    this is the class used, yes, it's Java.
    link for online execution (http://tpcg.io/H43Pe8)
    package neverwinter; import java.security.SecureRandom; public class Neverwinter { private static final int NUM_ROLLS = 1000000; public static void main(String[] args) { int[] rolls = new SecureRandom().ints(NUM_ROLLS, 1, 101).toArray(); int breakStreak = 0; final int MAX_BREAK_STREAK = 150; int success = 0; int breakStreakActivated = 0; for (int roll : rolls) { if (breakStreak >= MAX_BREAK_STREAK) { success++; breakStreak = 0; breakStreakActivated++; continue; } if (roll == 1) { success++; breakStreak = 0; continue; } breakStreak++; } System.out.printf("Rolls=%,d", NUM_ROLLS); System.out.println(); System.out.printf("Break streak activated=%,d", breakStreakActivated); System.out.println(); System.out.printf("Natural success=%,d", success - breakStreakActivated); System.out.println(); System.out.printf("Success=%,d", success); System.out.println(); System.out.printf("Failure=%,d", NUM_ROLLS - success); System.out.println(); System.out.printf("Failure chance=%,f", ((double) NUM_ROLLS - success) / NUM_ROLLS); } }
    You lost me.
  • nisckisnisckis Member, NW M9 Playtest Posts: 655 Arc User
    edited March 2019
    If you use a ward you have a 1% (0.01) chance of success so that is a 99% (0,99) of failure.
    With the new break streak system, if you fail 150 times in the same upgrade you will automatically succeed at the 151 try, it doesn't need to be in the same refining session, just the same item, and every item saves their own number of upgrade failures.
    It would be great to know what happens with the current break streak if that enchant gets stacked with others or if it can't be stacked unless it has a zero break streak value.
    People were asking for a price reduction in Coal wards because of this but I thought it didn't make any sense so I did some coding which simulates 1 million tries of upgrading an enchant with a 1% chance of success using the new break streak system.

    As it can be seen:
    • "Natural success" is approximately 10.000, which is a 1% in a 1 million pool, that is when you throw 1 in a D100.
    • "Break streak" activates around 2.800 times in a 1 million pool, that is around 2800 times you failed 150 times in a row.
    • "Success" is just the sum of "Natural sucess" and "Break streak", that is how many times you upgraded.
    • "Failure" is 1 million minus "Success", that is how many wards you would burn.
    • So "Failure chance" is the global probability of failing the upgrade with the new system, which is 0,9872 that translates to 98,72% of failure, instead of the original 99%.
    So in conclusion, no, Coals don't need any price reduction. The new system just makes you don't want to come to the forums saying that the system is broken, it just makes sure that when you have a really bad luck day, you don't burn all your ward stacks.
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User
    nisckis said:

    If you use a ward you have a 1% (0.01) chance of success so that is a 99% (0,99) of failure.
    With the new break streak system, if you fail 150 times in the same upgrade you will automatically succeed at the 151 try, it doesn't need to be in the same refining session, just the same item, and every item saves their own number of upgrade failures.
    It would be great to know what happens with the current break streak if that enchant gets stacked with others or if it can't be stacked unless it has a zero break streak value.
    People were asking for a price reduction in Coal wards because of this but I thought it didn't make any sense so I did some coding which simulates 1 million tries of upgrading an enchant with a 1% chance of success using the new break streak system.

    As it can be seen:

    • "Natural success" is approximately 10.000, which is a 1% in a 1 million pool, that is when you throw 1 in a D100.
    • "Break streak" activates around 2.800 times in a 1 million pool, that is around 2800 times you failed 150 times in a row.
    • "Success" is just the sum of "Natural sucess" and "Break streak", that is how many times you upgraded.
    • "Failure" is 1 million minus "Success", that is how many wards you would burn.
    • So "Failure chance" is the global probability of failing the upgrade with the new system, which is 0,9872 that translates to 98,72% of failure, instead of the original 99%.
    So in conclusion, no, Coals don't need any price reduction. The new system just makes you don't want to come to the forums saying that the system is broken, it just makes sure that when you have a really bad luck day, you don't burn all your ward stacks.
    I'll have to recheck my math then; perhaps I had a logic error somewhere.
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User
    edited March 2019

    nisckis said:

    If you use a ward you have a 1% (0.01) chance of success so that is a 99% (0,99) of failure.
    With the new break streak system, if you fail 150 times in the same upgrade you will automatically succeed at the 151 try, it doesn't need to be in the same refining session, just the same item, and every item saves their own number of upgrade failures.
    It would be great to know what happens with the current break streak if that enchant gets stacked with others or if it can't be stacked unless it has a zero break streak value.
    People were asking for a price reduction in Coal wards because of this but I thought it didn't make any sense so I did some coding which simulates 1 million tries of upgrading an enchant with a 1% chance of success using the new break streak system.

    As it can be seen:

    • "Natural success" is approximately 10.000, which is a 1% in a 1 million pool, that is when you throw 1 in a D100.
    • "Break streak" activates around 2.800 times in a 1 million pool, that is around 2800 times you failed 150 times in a row.
    • "Success" is just the sum of "Natural sucess" and "Break streak", that is how many times you upgraded.
    • "Failure" is 1 million minus "Success", that is how many wards you would burn.
    • So "Failure chance" is the global probability of failing the upgrade with the new system, which is 0,9872 that translates to 98,72% of failure, instead of the original 99%.
    So in conclusion, no, Coals don't need any price reduction. The new system just makes you don't want to come to the forums saying that the system is broken, it just makes sure that when you have a really bad luck day, you don't burn all your ward stacks.
    I'll have to recheck my math then; perhaps I had a logic error somewhere.
    Rerunning the whole thing, I still find that the average number of wards consumed is 78.

    There is a 100% chance of needing 1 or more wards. Because there's a 99% failure chance, there is a 99% chance of needing 2 or more wards. The chance of needing exactly one ward is equal to the chance of needing 1 or more wards (100%) minus the chance of needing 2 or more wards (99%), or 1%. We continue this formula down to the chance of needing 150 wards.

    The chance of needing 151 wards is equal to 1 - the sum of all other probabilities, about 22%.

    You then just multiply each probability by the number of wards (for instance, .01 times 1, .0099 *2 and so forth). This gives you the average number of preservation wards consumed.

    This number, as it turns out, is 78.07627306

    If someone sees a logic error in my math, let me know. But if there's no error in the math, then the simulation either A.) Has a logic error B.) is using the wrong streak breaker or C.) Just had a very odd sample.

    Or D.) Human understanding of probability is inherently flawed.
  • plasticbatplasticbat Member, NW M9 Playtest Posts: 12,408 Arc User
    edited March 2019

    nisckis said:

    If you use a ward you have a 1% (0.01) chance of success so that is a 99% (0,99) of failure.
    With the new break streak system, if you fail 150 times in the same upgrade you will automatically succeed at the 151 try, it doesn't need to be in the same refining session, just the same item, and every item saves their own number of upgrade failures.
    It would be great to know what happens with the current break streak if that enchant gets stacked with others or if it can't be stacked unless it has a zero break streak value.
    People were asking for a price reduction in Coal wards because of this but I thought it didn't make any sense so I did some coding which simulates 1 million tries of upgrading an enchant with a 1% chance of success using the new break streak system.

    As it can be seen:

    • "Natural success" is approximately 10.000, which is a 1% in a 1 million pool, that is when you throw 1 in a D100.
    • "Break streak" activates around 2.800 times in a 1 million pool, that is around 2800 times you failed 150 times in a row.
    • "Success" is just the sum of "Natural sucess" and "Break streak", that is how many times you upgraded.
    • "Failure" is 1 million minus "Success", that is how many wards you would burn.
    • So "Failure chance" is the global probability of failing the upgrade with the new system, which is 0,9872 that translates to 98,72% of failure, instead of the original 99%.
    So in conclusion, no, Coals don't need any price reduction. The new system just makes you don't want to come to the forums saying that the system is broken, it just makes sure that when you have a really bad luck day, you don't burn all your ward stacks.
    I'll have to recheck my math then; perhaps I had a logic error somewhere.
    Rerunning the whole thing, I still find that the average number of wards consumed is 78.

    There is a 100% chance of needing 1 or more wards. Because there's a 99% failure chance, there is a 99% chance of needing 2 or more wards. The chance of needing exactly one ward is equal to the chance of needing 1 or more wards (100%) minus the chance of needing 2 or more wards (99%), or 1%. We continue this formula down to the chance of needing 150 wards.

    The chance of needing 151 wards is equal to 1 - the sum of all other probabilities, about 22%.

    You then just multiply each probability by the number of wards (for instance, .01 times 1, .0099 *2 and so forth). This gives you the average number of preservation wards consumed.

    This number, as it turns out, is 78.07627306

    If someone sees a logic error in my math, let me know. But if there's no error in the math, then the simulation either A.) Has a logic error B.) is using the wrong streak breaker or C.) Just had a very odd sample.

    Or D.) Human understanding of probability is inherently flawed.
    The sentence "There is a 100% chance of needing 1 or more wards" does not sound right to me.
    There is a chance you use 0 ward. If you mean your sample never did that, just ignore what I said.
    *** The game can read your mind. If you want it, you won't get it. If you don't expect to get it, you will. ***
  • muminekm#3459 muminekm Member Posts: 248 Arc User
    @nisckis The basis of your simulation is wrong. You don't want to calulcate average chance of failure (with 1000000 seperate rolls) but average number of wards required to upgrade enchant. For example in this simple python script:


    import random enchants = 1000 streak_max = 150 streaks = [] streak_curr = 0 success = 0 for x in range(enchants): streak_curr = 0 while True: num = random.randint(1,100) if num == 1: streaks.append(streak_curr) break streak_curr+=1 if streak_curr == 150: streaks.append(streak_curr) break print(len(streaks)) print(sum(streaks)/len(streaks))


    It's not really truly random but for 1000 enchants average required number wards for three runs of program: 78.02, 77.001, 78.301
  • nisckisnisckis Member, NW M9 Playtest Posts: 655 Arc User

    There is a 100% chance of needing 1 or more wards.

    That's wrong, you could just throw the dice and get a 1 so you would need no wards at all.
  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User

    nisckis said:

    If you use a ward you have a 1% (0.01) chance of success so that is a 99% (0,99) of failure.
    With the new break streak system, if you fail 150 times in the same upgrade you will automatically succeed at the 151 try, it doesn't need to be in the same refining session, just the same item, and every item saves their own number of upgrade failures.
    It would be great to know what happens with the current break streak if that enchant gets stacked with others or if it can't be stacked unless it has a zero break streak value.
    People were asking for a price reduction in Coal wards because of this but I thought it didn't make any sense so I did some coding which simulates 1 million tries of upgrading an enchant with a 1% chance of success using the new break streak system.

    As it can be seen:

    • "Natural success" is approximately 10.000, which is a 1% in a 1 million pool, that is when you throw 1 in a D100.
    • "Break streak" activates around 2.800 times in a 1 million pool, that is around 2800 times you failed 150 times in a row.
    • "Success" is just the sum of "Natural sucess" and "Break streak", that is how many times you upgraded.
    • "Failure" is 1 million minus "Success", that is how many wards you would burn.
    • So "Failure chance" is the global probability of failing the upgrade with the new system, which is 0,9872 that translates to 98,72% of failure, instead of the original 99%.
    So in conclusion, no, Coals don't need any price reduction. The new system just makes you don't want to come to the forums saying that the system is broken, it just makes sure that when you have a really bad luck day, you don't burn all your ward stacks.
    I'll have to recheck my math then; perhaps I had a logic error somewhere.
    Rerunning the whole thing, I still find that the average number of wards consumed is 78.

    There is a 100% chance of needing 1 or more wards. Because there's a 99% failure chance, there is a 99% chance of needing 2 or more wards. The chance of needing exactly one ward is equal to the chance of needing 1 or more wards (100%) minus the chance of needing 2 or more wards (99%), or 1%. We continue this formula down to the chance of needing 150 wards.

    The chance of needing 151 wards is equal to 1 - the sum of all other probabilities, about 22%.

    You then just multiply each probability by the number of wards (for instance, .01 times 1, .0099 *2 and so forth). This gives you the average number of preservation wards consumed.

    This number, as it turns out, is 78.07627306

    If someone sees a logic error in my math, let me know. But if there's no error in the math, then the simulation either A.) Has a logic error B.) is using the wrong streak breaker or C.) Just had a very odd sample.

    Or D.) Human understanding of probability is inherently flawed.
    The sentence "There is a 100% chance of needing 1 or more wards" does not sound right to me.
    There is a chance you use 0 ward. If you mean your sample never did that, just ignore what I said.
    Oh! So there was a logic error! I forgot that the successful ward isn't consumed.

    Which ... pulls the average number of wards used down even further.
  • nisckisnisckis Member, NW M9 Playtest Posts: 655 Arc User
    edited March 2019

    @nisckis The basis of your simulation is wrong. You don't want to calculate average chance of failure (with 1000000 seperate rolls) but average number of wards required to upgrade enchant. For example in this simple python script:


    import random enchants = 1000 streak_max = 150 streaks = [] streak_curr = 0 success = 0 for x in range(enchants): streak_curr = 0 while True: num = random.randint(1,100) if num == 1: streaks.append(streak_curr) break streak_curr+=1 if streak_curr == 150: streaks.append(streak_curr) break print(len(streaks)) print(sum(streaks)/len(streaks))


    It's not really truly random but for 1000 enchants average required number wards for three runs of program: 78.02, 77.001, 78.301
    What?, what the what?, you are right, I calculated the probability of failure of every roll with the new system, not how many wards in average are needed with the new system. I have updated the post, thanks a lot @muminekm#3459
  • cdnbisoncdnbison Member, NW M9 Playtest Posts: 806 Arc User


    The goal, one imagines, is to make those previously useless green and blue insignias that you get from skill nodes and the like useful again.

    "Useless" blues? Those are what I put on my alts! (Greens.. yeah, totally gone to the great RP pool in the sky).

  • lowjohnlowjohn Member, NW M9 Playtest Posts: 1,061 Arc User

    Why insignia refinement must using insignia same type and with different rank as reagent? why not using mark of potency or enchanting stone?
    Will you give us extra bag slot? Insignias will occupied more slot in inventory imho.

    The goal, one imagines, is to make those previously useless green and blue insignias that you get from skill nodes and the like useful again.
    I'm not sure if you noticed, but for the last few weeks on Live the green insignia from skill nodes and monster drops have been unbound instead of character-bound the way they were before.

    So there will be a market, both to sell the green insignia that players looking for Legendary bonuses need, and to buy the green insignia you're short on.
  • lowjohnlowjohn Member, NW M9 Playtest Posts: 1,061 Arc User

    lowjohn said:

    (Other obvious version: Have two variables, one "Streak Breaker" and one "upgrade attempts count", and increment UAC instead of decrementing SB, and your check is instead "does UAC equal SB? If so, upgrade automatically. If not, normal attempt and increment UAC". Exact same behaviour, just different way of getting there.)


    "Streak Breaker" is a global constant for each rank rather than a variable. There is no need to keep in the enchant.

    Dev noworries has confirmed a page or two back in this thread that it is stored in each enchant, like RP. The reason for this is so that if you have to change stacks or run out and start again next payday the enchant will "remember" where you were in the streak and you will not have to start all over again. It would suck to be one attempt away from the streak breaker and run out of character-bound wards, switch to a stack of account-bound wards and start over at attempt number one...
    What he said is correct with a programmer's hat.
    The "Steak breaker" of each type of enchantment is a constant value stored in a global table. e.g. says, R15 streak breaker is 150. 150 is a constant value stored somewhere in a global table.

    The "streak counter" is a variable stored in each enchantment item which is increment every time you fail to refine it. It is a number stored in each item started with 0.

    What he mean is it does not need 2 variables in the item. You only need one. lowjohn did not exactly say it needs 2 for each item neither but one may think he said it that way.
    Is it really necessary to store a separate table for the breaker? I mean, the mathematical function is (1/ProbabilityOfSuccess)*1.5 isn't it? So is it any more efficient to store it in a table and then look up the list than to just run a check against the mathematical formula?

    That assumes that my understanding of what the streakbreaker is for any given rank is right of course-I don't recall what the table is.
    The constant streak breaker number is stored in a table with something like:
    R1 2
    R2 4
    R3 8
    ....
    R15 150

    The table can just be an array in program memory or read (and cached) from a database table.
    Of course, they can also just use math to do calculation based on the probability number as you said if that is their design.

    One may copy the value to the streak counter of each item to decrement it.
    Or, increment the streaker counter of each item to see if it reaches the streak breaker number
    Right, but I'm just trying to think of what's the most "efficient." But that's sort of sketchy, because what are you optimizing for? If you never want to store anything, you do the math each time. But since the memory allocation for one table is pretty small, I suggest that a simple lookup on a table is easier than a round(1/X*Y) type formula.
    In my experience, comparing with lookup table is always faster than math calculation.

    In low level assembler:
    store X to register, store Y to register, compare, get the result.

    Doing any math calculation (except double or half an integer type of calculation such as 2x, 4x, .. 1/2,1/4, ...) is a lot slower than lookup table.
    I'm usually trying to avoid having to store things in memory, but since the lookup table is really small, it's probably worth just creating the table.
    Also, having it as a global variable and not stored-in-the-item makes it easier to alter later: If they decide the 1% Streak Breaker needs to be 180 but the 30% Streak Breaker would be better served to be "2", making it a global table means not needing to update the internal status of every enchant of the game just because you've changed the math.
  • altorothaltoroth Member Posts: 5 Arc User
    edited March 2019
    Tried exchanging weapon enchants at the vendor and discovered:
    Plague fire rank 14 weapon enchant is showing as 2% bonus damage, all the other enchants are 5% at rank 14.
    Checked plague fire rank 13 and it is 4.5%.
    Post edited by altoroth on
  • lowjohnlowjohn Member, NW M9 Playtest Posts: 1,061 Arc User

    Enchantment values still scale between different level 70 zones.

    Radiant in Protector's Enclave gives 1080 power.
    Radiant in Dread Ring gives 420 power.

    Is this a bug or intended behavior?

    Intended behaviour! @noworries#8859 says in a different thread:

    Scaling isn't a proportional adjustment, scaling has a limit on how high an item level can be for a specific type of item, things above that are brought down to that level. That does mean different rank items can end up at the same effectiveness in scaled content.

    As far as the Underdark/Sharandar, that would be an issue with where Underdark was set. Chult, Ravenloft, Dreadring don't all scale to the same place even though they are all level 70. Chult is meant to be a more powerful area than Dreadring, so the scaling allows a higher level of items in Chult than it does in Dreadring.



    So, that's intended. Dread Ring, being Mod 2, is an "easy" zone but that comes with a lower cap on how good your gear CAN BE in the Dread Ring. All your gear that's better than the Dread Ring's cap is lowered to the cap, regardless of whether it was one level over the cap or 9 levels over the cap.
  • lordseth1985lordseth1985 Member, NW M9 Playtest Posts: 319 Arc User
    altoroth said:

    Tried exchanging weapon enchants at the vendor and discovered:
    Plague fire rank 14 weapon enchant is showing as 2% bonus damage, all the other enchants are 5% at rank 14.
    Checked plague fire rank 13 and it is 4.5%.

    All weapon enchants shoudl give 3-5% bonus damage on rank 14, or not? Cuz I saw some enchants giving 4%, others giving 3,5% bonus dmg... all of this is WAI or not?
    Avestruz.Q.T.Seduz - Rogue, natural born assassin.
  • zimxero#8085 zimxero Member Posts: 876 Arc User
    I own one complete set of Triple-Stat enchantments (including on my companion). Please allow players to exchange Single/Double/Triple Enchantments for Single stat Runestones, or our pets will have nothing we can equip.

  • theycallmetomutheycallmetomu Member, NW M9 Playtest Posts: 1,861 Arc User
    lowjohn said:

    lowjohn said:

    (Other obvious version: Have two variables, one "Streak Breaker" and one "upgrade attempts count", and increment UAC instead of decrementing SB, and your check is instead "does UAC equal SB? If so, upgrade automatically. If not, normal attempt and increment UAC". Exact same behaviour, just different way of getting there.)


    "Streak Breaker" is a global constant for each rank rather than a variable. There is no need to keep in the enchant.

    Dev noworries has confirmed a page or two back in this thread that it is stored in each enchant, like RP. The reason for this is so that if you have to change stacks or run out and start again next payday the enchant will "remember" where you were in the streak and you will not have to start all over again. It would suck to be one attempt away from the streak breaker and run out of character-bound wards, switch to a stack of account-bound wards and start over at attempt number one...
    What he said is correct with a programmer's hat.
    The "Steak breaker" of each type of enchantment is a constant value stored in a global table. e.g. says, R15 streak breaker is 150. 150 is a constant value stored somewhere in a global table.

    The "streak counter" is a variable stored in each enchantment item which is increment every time you fail to refine it. It is a number stored in each item started with 0.

    What he mean is it does not need 2 variables in the item. You only need one. lowjohn did not exactly say it needs 2 for each item neither but one may think he said it that way.
    Is it really necessary to store a separate table for the breaker? I mean, the mathematical function is (1/ProbabilityOfSuccess)*1.5 isn't it? So is it any more efficient to store it in a table and then look up the list than to just run a check against the mathematical formula?

    That assumes that my understanding of what the streakbreaker is for any given rank is right of course-I don't recall what the table is.
    The constant streak breaker number is stored in a table with something like:
    R1 2
    R2 4
    R3 8
    ....
    R15 150

    The table can just be an array in program memory or read (and cached) from a database table.
    Of course, they can also just use math to do calculation based on the probability number as you said if that is their design.

    One may copy the value to the streak counter of each item to decrement it.
    Or, increment the streaker counter of each item to see if it reaches the streak breaker number
    Right, but I'm just trying to think of what's the most "efficient." But that's sort of sketchy, because what are you optimizing for? If you never want to store anything, you do the math each time. But since the memory allocation for one table is pretty small, I suggest that a simple lookup on a table is easier than a round(1/X*Y) type formula.
    In my experience, comparing with lookup table is always faster than math calculation.

    In low level assembler:
    store X to register, store Y to register, compare, get the result.

    Doing any math calculation (except double or half an integer type of calculation such as 2x, 4x, .. 1/2,1/4, ...) is a lot slower than lookup table.
    I'm usually trying to avoid having to store things in memory, but since the lookup table is really small, it's probably worth just creating the table.
    Also, having it as a global variable and not stored-in-the-item makes it easier to alter later: If they decide the 1% Streak Breaker needs to be 180 but the 30% Streak Breaker would be better served to be "2", making it a global table means not needing to update the internal status of every enchant of the game just because you've changed the math.
    See, that's forward thinking for ya.
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