Help me with my math homework. :)

CornHilario - Heavens Tear

I tried posting it in the off-topic discussion, but those guys said "get this math out of here and take it to the archer forums."

1. Find the sum of the infinite series:

4(2/3)^k, k(initial)=0.

Four times two-thirds to the k(initial) power, k=0.

I don't know how to type out the exact equation, but if you have questions about the question, just ask.

2. Use mathematical induction to prove the formula for every integer on n.

1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).

__________________________________________________________________________

TY, archers! I hope I can rely on you guys if I need questions asked. Unlike those guys at the off-topic discussion, can't help kids with their homework. Stop playing PW and go back to college!!! b:angry

fulgida

1. 12 (now, ask yourself: do you trust me? (Everyone that posts after me, tell him that the answer is 12 and see if he falls for it!))

2. is self evident

b:chuckle

CornHilario - Heavens Tear

oh yeah, i did finished my homework. by myself lol.

1. yes, it is 12.

2. no comment. b:shocked

Devoted - Lost City

CornHilario - Heavens Tear wrote: »

I tried posting it in the off-topic discussion, but those guys said "get this math out of here and take it to the archer forums."

1. Find the sum of the infinite series:

4(2/3)^k, k(initial)=0.

Four times two-thirds to the k(initial) power, k=0.

I don't know how to type out the exact equation, but if you have questions about the question, just ask.

2. Use mathematical induction to prove the formula for every integer on n.

1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).

__________________________________________________________________________

TY, archers! I hope I can rely on you guys if I need questions asked. Unlike those guys at the off-topic discussion, can't help kids with their homework. Stop playing PW and go back to college!!! b:angry

1) For infinite geometric series that follow the format ar^k the sum of the series is a / ( 1 - r).

In this case a = 4, r = 2/3:

s = 12;

2) P(n) = 1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).


Base Case n = 0:

P(0) = 0 = 0 therefore P(0) is true.

Inductive step:

For n > 0 assume P(n-1) is true.

1+(3/2)+2+(5/2)+...+(1/2)(n+1) = 1+(3/2)+2+(5/2)+...+(1/2)(n) + (1/2)(n+1)
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = ((n-1)/4)(n+2) + (1/2)(n+1)
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = [(n-1)(n+2) + 2(n+1)]/4
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n^2 + 3n) / 4
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).
QED


You're lucky I have exams this week and I figured this was an old refresher :x

Teppeii - Dreamweaver

It's official. Archer forums > all other fourms.

Moranine - Lost City

Devoted - Lost City wrote: »

1) For infinite geometric series that follow the format ar^k the sum of the series is a / ( 1 - r).

In this case a = 4, r = 2/3:

s = 12;

2) P(n) = 1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).


Base Case n = 0:

P(0) = 0 = 0 therefore P(0) is true.

Inductive step:

For n > 0 assume P(n-1) is true.

1+(3/2)+2+(5/2)+...+(1/2)(n+1) = 1+(3/2)+2+(5/2)+...+(1/2)(n) + (1/2)(n+1)
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = ((n-1)/4)(n+2) + (1/2)(n+1)
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = [(n-1)(n+2) + 2(n+1)]/4
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n^2 + 3n) / 4
1+(3/2)+2+(5/2)+...+(1/2)(n+1) = (n/4)(n+3).
QED


You're lucky I have exams this week and I figured this was an old refresher :x

I love you Devoted.

CornHilario - Heavens Tear

ty all. from now on, i will post my math questions here lol

HexOmega - Dreamweaver

CornHilario - Heavens Tear wrote: »

I tried posting it in the off-topic discussion, but those guys said "get this math out of here and take it to the archer forums."

b:chuckleb:laugh

the word is spreading

rofl

PenutButer - Dreamweaver

I love everyone that posts on the archer forums specially fishbone man

Esnemyl - Dreamweaver

Gah... what is this I dont even X_X
Its' either that I have entered the matrix.. or I am just dumb because maths is my worse subject.

Dyskrasia - Heavens Tear

Esnemyl - Dreamweaver wrote: »

Gah... what is this I dont even X_X
Its' either that I have entered the matrix.. or I am just dumb because maths is my worse subject.

You have to get to at least level 90 before you'll be good at math, sorry.

KibblesnBitz - Sanctuary

Dyskrasia - Heavens Tear wrote: »

You have to get to at least level 90 before you'll be good at math, sorry.

Hahahahahaha win. b:laugh

Esnemyl - Dreamweaver

Lol, yes I do really suck at maths.. it's been my worst subject since forever. XD
No matter what level I will be, i'm never gonna be good at it.

truekossy

Esnemyl - Dreamweaver wrote: »

Lol, yes I do really suck at maths.. it's been my worst subject since forever. XD
No matter what level I will be, i'm never gonna be good at it.

Don't worry, you just have to hit 90. All archers become godly math experts once they get to that level.

That or they realize that they're not really archers and reroll.

NekoCreeper - Heavens Tear

truekossy wrote: »

Don't worry, you just have to hit 90. All archers become godly math experts once they get to that level.

That or they realize that they're not really archers and reroll.

Lhttp://pwi-forum.perfectworld.com/images/buttons/submit_reply.gifmao b:laughb:laughb:laughb:laugh

XylolyX - Heavens Tear

Esnemyl - Dreamweaver wrote: »

Gah... what is this I dont even X_X
Its' either that I have entered the matrix.. or I am just dumb because maths is my worse subject.

Glad to know I'm not the only one.

fulgida

Esnemyl - Dreamweaver wrote: »

Gah... what is this I dont even X_X
Its' either that I have entered the matrix.. or ...

Coming soon:

An archer's guide to gauss-jordan reduction.

(Welcome to the real world.)

b:chuckle

Tygurr - Sanctuary

....... O.o

*casually walks out the room, slowly shaking head in disbelief*