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Forums > Home› Feedback› Duty Officer System and R&D

DOFF stacking percentages and their results

weezedogweezedog Member Posts: 0 Arc User
edited August 2012 in Duty Officer System and R&D
I did some testing and stacked 3 (the max) blue quality energy weapons officers each with a 25% chance to reduce the recharge time on beams abilities. You would think this would give a 75% chance to reduce the cooldown of beam abilities (25% x 3 = 75%)
To test this, I casted Beam Overload 50 times in a row, and only 26 times did it reduced the cooldown on the ability. Obviously this is only ~50%, so what are the rules on stacking DOFFs, are there dimishing returns or is it broken?
Post edited by weezedog on

Comments

  • tjexcimer500tjexcimer500 Member Posts: 0 Arc User
    edited July 2012
    If instead of stacking it runs the 25% chance three times in a row (one for each DOff assigned), then the probability is 57.8125%.

    My reasoning behind this:
    This becomes a binomial probability problem with at least one success out of the three DOffs where there is a 25% probability of success, and obviously a 75% probability of failure.

    3C1(.25)(.75)^2 + 3C2(.25)^2(.75) + 3C3(.25)^3 = 0.578125

    26/50 = 0.52 - which is close to this theoretical probability given only 50 chances.

    If this is the way it works, then for two DOffs there will be a 43.75% chance of reducing the time.
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  • weezedogweezedog Member Posts: 0 Arc User
    edited July 2012
    That seems to be what it is doing, running the 25% chance 3 times in a row. In the tooltips for my beam weapons it shows "25% chance..." three times i.e.:

    "25% chance..."
    "25% chance..."
    "25% chance..."

    instead of "75% chance..."

    It seems counter intuitive for it to do things that way, and it certainly is a hefty diminished return from the expected outcome.
  • darthvicious666darthvicious666 Member Posts: 54 Arc User
    edited August 2012
    Nevermind. Lol.
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  • defcon1776defcon1776 Member Posts: 313 Arc User
    edited August 2012
    tjexcimer500 wrote: »
    If instead of stacking it runs the 25% chance three times in a row (one for each DOff assigned), then the probability is 57.8125%.

    My reasoning behind this:
    This becomes a binomial probability problem with at least one success out of the three DOffs where there is a 25% probability of success, and obviously a 75% probability of failure.

    3C1(.25)(.75)^2 + 3C2(.25)^2(.75) + 3C3(.25)^3 = 0.578125

    26/50 = 0.52 - which is close to this theoretical probability given only 50 chances.

    If this is the way it works, then for two DOffs there will be a 43.75% chance of reducing the time.

    ^^ Trust the math guys ^^
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  • nnitennite Member Posts: 32 Arc User
    edited August 2012
    tjexcimer500 wrote: »
    If instead of stacking it runs the 25% chance three times in a row (one for each DOff assigned), then the probability is 57.8125%.

    My reasoning behind this:
    This becomes a binomial probability problem with at least one success out of the three DOffs where there is a 25% probability of success, and obviously a 75% probability of failure.

    3C1(.25)(.75)^2 + 3C2(.25)^2(.75) + 3C3(.25)^3 = 0.578125

    26/50 = 0.52 - which is close to this theoretical probability given only 50 chances.

    If this is the way it works, then for two DOffs there will be a 43.75% chance of reducing the time.

    This math sounds correct regard to the design of the game.
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