Can anyone tell me how many ways that you could arrange character classes in a 5 player party? For example, you could have 5 rogues in a party. Or you could have a mixture of sorts such as a Guardian, hunter, cleric, GWF and Wizard.
The factors are 7 different classes and 5 member parties. Also remember that we can have more than 1 of the same! I think permutations is the maths we use here. To make it a little simpler we'll make it all 5 player parties...
A permutation is what you would use when the order matters. Combination is what you want here and with repetition since a class can be represented multiple times. The formula for N things taken R at a time is:
(n+r-1)! / r!(n-1)!
As stricklyevil provided, (7+5-1)! / 5!(7-1)! = 462. Not as many combinations as you might think.
Thank you strictlyevil and mungsu! I would have never worked it out myself. I think my question might have been a little to difficult for high school having now seen the formula.
I can now see that if you were testing all permutations for both multi player and dungeons then it would be quite a challenge! My question now is what is the best 5 characters for a party? Some have suggested 2 clerics, 2 rogue and a wizard! Others say more of a mixture!
In a perfect world you would want a healer, tank and 3 DPS. The dps can be interchanged depending on the needs of the party and depending on the dungeon. But, this isn't a perfect world and things don't work that way. On current Xbox content there isn't much emphasis on team variation as there are in other games. With the right skills you could have a team of all DPS and clear a dungeon just fine. Though I will say that having the previously mentioned set up of a tank, healer and 3 DPS will more times than not make for a more enjoyable and easier experience.
Best party composition is four DPS and one GF or DC, but DPS-only works well too. My favorite group is two TRs, two CWs, and any other class (preferably a DC that knows how to tank/kite).
Comments
7 to the 5th, no?
[edit] I didn't discount for the number of repetitions (i.e. 11115 being 15111); what was the formula for this?
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I forfeit my answer. This guy wins by default.
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(n+r-1)! / r!(n-1)!
As stricklyevil provided, (7+5-1)! / 5!(7-1)! = 462. Not as many combinations as you might think.
I can now see that if you were testing all permutations for both multi player and dungeons then it would be quite a challenge! My question now is what is the best 5 characters for a party? Some have suggested 2 clerics, 2 rogue and a wizard! Others say more of a mixture!
Thanks
Wade
.
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