I did some number crunching, and I came up with a formula that describes the optimal relation of Power and Critical Strike in module 6. The interesting thing is that there is no best ratio between Power and Critical Strike, but a best offset between those two stats. The best offset is determined by your base critical chance and your critical severity:
c: points in your 'Critical Strike' stat
p: points in your 'Power' stat
b: your base critical chance (how high your chance to hit critically is if you have 0 points in the 'Critical Strike' stat)
s: your 'Critical Severity'
c - p = 40000 * (1 - b - 1/s)
For example, my GF with 132,2% crit severity (s = 1,322) and a base critical chance of 8% (b = 0,08) would need 6543 points more in Critical Strike than in Power to be optimized in module 6. Looks like I need some more points in Critical Chance so I reach 19133 ... Nope, not going to happen, I better look for a different weapon enchantment, forget about dps, or train my 'Enforced Singularity'. :cool:
How did you acheive to such formula?
It seem logical .
in mod6 you gain 1% per 400 stat points in power, same for crit. You start with an equation that displays the damage-multiplier due to your damage bonus from power and your additional damage from critical hits:
Then you create the first derivative of that equation and define it to equal 0. (we are looking for a maximum here). Multiply that equation by 40000 to streamline it, and it will look like this:
0 = -s + 1 + sa/40000 - 2ps/40000 + sb
Next you shuffle stuff a bit around so that 'a' is alone on one side of the equation, and you get this:
a = 2p + 40000 * (1 - b - 1/s)
Now we can replace 'a' in 'p + c = a' (which we defined earlier). Look sharply at what we got now, and you realize, that there is no optimal ratio p/c, because we cannot make p/c stand exclusively on one side of the equation. Instead there is an optimal offset, and thus we decide to single out 'c - p' on one side of the equation to express the offset-character of this problem and give the equation a meaningfull look:
My s is 182,2% and b is 22%. Seems like I need 9.2k more points in my crit stat than in power for crit build to be effective? Thought crit severity would decrease the required crit chance. Never was good at maths tbh ;(
Not sure what are my stats goint to be in m6 yet anyway.
Thanks for the explanation.
So a mage at 50% crit and 145% sevetity will end with a delta of -7586.. in short, my power need 7600 points more in power than in crit.
For completness, crit cap at 100% and armor penetration sjould be included too.
On the contrary, the more crit severity you have, the more crit gets effective.
I tried to say the more crit severity you have, the lower crit chance plank when vorpal becomes more effective then the rest enchantments :P No wonder all Magus Cambions sky rocketed today -.-
I made a spreadsheet where one can enter a character's base critical strike, critical severity and the sum of their power and critical strike stat (yellow cells). The spreadsheet will then display your optimal values for power, critical strike, the highest possible damage multiplier and a nice diagramm showing the Damage multiplier versus power/crit distribution. That diagramm automagically changes if you enter new values.
Edit: Minor error in the spreadsheed: The Text "Base Critical Strike" in cell E4 should say "Base Critical Chance". This doesn't affect the math or the curve. I fixed this and attached the new spreadsheet (powercrit5.odt) to this posting.
Comments
It seem logical .
d.multiplier = (1 + p/40000) * (1 + (c/40000 +b)*s)
Then you assume that you have a limited pool of stat points to allocate and thus define the sum of power and crit constant. I call this constant 'a':
p + c = a
You get rid of the brackets in the initial formula and replace 'c' with 'a-p':
d.multiplier = 1 + (sa-sp)/40000 + sb + p/40000 + (sap-spp)/16000000 + sbp/40000
Then you create the first derivative of that equation and define it to equal 0. (we are looking for a maximum here). Multiply that equation by 40000 to streamline it, and it will look like this:
0 = -s + 1 + sa/40000 - 2ps/40000 + sb
Next you shuffle stuff a bit around so that 'a' is alone on one side of the equation, and you get this:
a = 2p + 40000 * (1 - b - 1/s)
Now we can replace 'a' in 'p + c = a' (which we defined earlier). Look sharply at what we got now, and you realize, that there is no optimal ratio p/c, because we cannot make p/c stand exclusively on one side of the equation. Instead there is an optimal offset, and thus we decide to single out 'c - p' on one side of the equation to express the offset-character of this problem and give the equation a meaningfull look:
c - p = 40000 * (1 - b - 1/s)
My s is 182,2% and b is 22%. Seems like I need 9.2k more points in my crit stat than in power for crit build to be effective? Thought crit severity would decrease the required crit chance. Never was good at maths tbh ;(
Not sure what are my stats goint to be in m6 yet anyway.
WTB Class Reroll please
So a mage at 50% crit and 145% sevetity will end with a delta of -7586.. in short, my power need 7600 points more in power than in crit.
For completness, crit cap at 100% and armor penetration sjould be included too.
Good work.
On the contrary, the more crit severity you have, the more crit gets effective.
I tried to say the more crit severity you have, the lower crit chance plank when vorpal becomes more effective then the rest enchantments :P No wonder all Magus Cambions sky rocketed today -.-
WTB Class Reroll please
Edit: Minor error in the spreadsheed: The Text "Base Critical Strike" in cell E4 should say "Base Critical Chance". This doesn't affect the math or the curve. I fixed this and attached the new spreadsheet (powercrit5.odt) to this posting.
c: 2246 points
p: 6155 points
b: 34% (your base critical chance)
s: 75% your 'Critical Severity'